Comments: 36
LoveAngel5 [2016-06-21 23:13:09 +0000 UTC]
You truly captured the dual nature of Galadriel and that is not easy to do.Β Really amazing rendering.Β I love it.
π: 0 β©: 1
Nastyfoxy In reply to LoveAngel5 [2016-06-25 19:17:51 +0000 UTC]
Thank you very much!
π: 0 β©: 0
tulipteardrops [2016-05-05 02:54:18 +0000 UTC]
amazing work
π: 0 β©: 1
BanishTheRobot [2015-12-26 21:27:37 +0000 UTC]
OMG, Looks alive. Β
π: 0 β©: 0
xOlelukoye [2015-11-06 08:21:12 +0000 UTC]
ΠΠΎΡΡΡΡΠ°ΡΡΠ΅!!!
π: 0 β©: 0
Ysydora [2015-09-16 07:50:55 +0000 UTC]
Haaaaa !!Too beautiful!! Β
π: 0 β©: 0
ahappierlife [2015-06-16 19:13:46 +0000 UTC]
I like the face: it seems to hide as much as it shows. An intriguing balance. The way she is looking slightly downwards adds a lot to the effectiveness. Thanks for making it available.
π: 0 β©: 1
Muselif In reply to Nastyfoxy [2015-06-04 17:01:18 +0000 UTC]
did you understand ?
π: 0 β©: 1
Nastyfoxy In reply to Muselif [2015-06-04 21:01:03 +0000 UTC]
Not sure that correctly understood. But the online translator gave a funny thing.
π: 0 β©: 1
Nastyfoxy In reply to Muselif [2015-06-05 16:59:55 +0000 UTC]
In any case, thanks for the positive )))))))
π: 0 β©: 1
ladyatropos [2015-05-24 11:50:15 +0000 UTC]
This is lovely! Which brand of water colour pencils do you use? I've heard very good things about Inktense.Β
π: 0 β©: 1
Nastyfoxy In reply to ladyatropos [2015-05-24 17:33:09 +0000 UTC]
Thank you! I use pencils Koh-i-Noor Mondeluz" 18 colors. It's not the best pencils. But they have a reasonable price.
π: 0 β©: 0
Nastyfoxy In reply to LegolasGoldy [2015-03-25 16:44:32 +0000 UTC]
Thank you very much. I think that there is nothing to worry about. Watercolor pencils even slightly simplify the task ))))
π: 0 β©: 1
777wolf [2015-03-09 13:37:05 +0000 UTC]
Amazing!
π: 0 β©: 1
Nastyfoxy In reply to 777wolf [2015-03-09 14:03:44 +0000 UTC]
Thank you!
π: 0 β©: 1
777wolf In reply to Nastyfoxy [2015-03-09 14:50:13 +0000 UTC]
You're welcome
π: 0 β©: 0
ladylatex555 [2015-03-07 21:55:43 +0000 UTC]
Lovely picture Anastasia.
π: 0 β©: 1