Comments: 26
Samhiel [2008-08-16 08:11:40 +0000 UTC]
He looks familiar to me. Oh well, nice job!!
π: 0 β©: 0
Eriath [2008-07-21 22:03:20 +0000 UTC]
Y estas dollis de dΓ³nde las sacΓ‘is? Porque son preciosas!!! Muy buena foto^^
π: 0 β©: 0
the-mirror-girl [2008-06-20 12:51:22 +0000 UTC]
Nice!
I WANT THAT HAIR!
π: 0 β©: 0
Noemnerys [2008-01-19 02:31:17 +0000 UTC]
Aghhh que mono >3<
π: 0 β©: 0
soulchainer [2008-01-07 01:28:10 +0000 UTC]
Asi que se llamaba Ellioth... El dollfo de AlaurΓ«
Es precioso. Yo tb le hice unas cuantas fotos si. Como no hacerlas. *__*
Me encantaba su pelo. Y sus ojos... parece que siempre brillan de una forma especial *__*
π: 0 β©: 1
sakurimake In reply to soulchainer [2008-01-07 12:58:53 +0000 UTC]
sii eran geniales sus ojos *O* tenian efecto Cullen >.<
π: 0 β©: 0
sakurimake In reply to tabeck [2007-12-30 12:59:03 +0000 UTC]
noo xDD they are not my dolls xDD
π: 0 β©: 1
tabeck In reply to sakurimake [2007-12-30 16:25:05 +0000 UTC]
wuuu whose doll? your friend's?hehe must be very expensive! =_=;
π: 0 β©: 1
sakurimake In reply to tabeck [2008-01-02 21:30:54 +0000 UTC]
yes, is from a girl (I don`t remember her name u_u) in a Doll Party
π: 0 β©: 0
hirou-kun [2007-12-24 00:26:46 +0000 UTC]
pewro ke guapo ke es el jodio elioth de pepa!
XDD
π: 0 β©: 1
sakurimake In reply to hirou-kun [2007-12-24 11:31:08 +0000 UTC]
siii, ahhhh gracias, aora me pongo y lo rectifico^^
π: 0 β©: 0
sakurimake In reply to SrtaMatsumoto [2007-12-24 11:30:14 +0000 UTC]
siii es super wapooo
nu me ongo seriota u_u ayer se me cruzaron los cables gomen nee
π: 0 β©: 0
arcthelove [2007-12-23 22:26:30 +0000 UTC]
bjd<3
This one has cool hair ^^
π: 0 β©: 1
sakurimake In reply to arcthelove [2007-12-23 23:11:46 +0000 UTC]
yes yes, the hair is beautiful ^^
π: 0 β©: 1
arcthelove In reply to sakurimake [2007-12-24 00:43:12 +0000 UTC]
I realized today that my little brother's friend has the facial shape of a bjd...and his hair acts the same...it's so weird 0_0
π: 0 β©: 1
reitantei [2007-12-23 22:23:17 +0000 UTC]
cool doll and photo :3
π: 0 β©: 1