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# Statistics
Favourites: 578; Deviations: 0; Watchers: 25
Watching: 65; Pageviews: 1786; Comments Made: 431; Friends: 65
# Interests
Favorite visual artist: I dunno.Favorite movies: LOTR, Hobbit, Harry Potter, Pirates of the Caribbean
Favorite TV shows: Who knows? *shrugs* But can I just say that I love Harry Potter Puppet Pals.How It Should Have Ended?
Favorite bands / musical artists: I love 21 Pilots, but my fav artist? BILLIE EILISH FOR THE WIN! My favorites are COPYCAT, idontwannabeyouanymore, bellyache, watch, my boy, you should see me in a crown, party favor (basically all of them, haha)
Favorite books: Percy Jackson (and any Rick Riordan series),Harry Potter, Wings of Fire, Chronicles of Narnia, especially NOT Twilight
Favorite writers: J.K. Rowling, Tui T Sutherland, J.R.R. Tolkien, Rick Riordan
Favorite games: The Hunger Games! I don't know... I don't want to be put in there, please.
Favorite gaming platform: What kind of question is this? ._.
Tools of the Trade: Just going to say, I am in so many fandoms, I don't even want to list this. You're welcome.
Other Interests: I am a proud Slytherin, and no hate on that. Slytherins aren't ALL evil, just some. I am an IceWing/RainWing in Wings of Fire!
# Comments
Comments: 41
jade-winglet-ask [2019-05-15 00:35:20 +0000 UTC]
I HAVE MOVED TO XsakuradrawsX !!
Please check out that page with my new and improved art
I would appreciate it if you watched and gave llamas to that account.Β
I AM NO LONGER USING THIS ACCOUNT
Thank you ^^
~Sakura
π: 0 β©: 0
jade-winglet-ask In reply to Wingedspirit890 [2019-02-03 18:01:15 +0000 UTC]
More like Hurricane TORTILLA
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jade-winglet-ask In reply to KomaCookie [2019-01-28 18:18:41 +0000 UTC]
Yw :3
I canβt believe I just found you
What the heck your art is beautiful
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KomaCookie In reply to jade-winglet-ask [2019-01-28 18:21:09 +0000 UTC]
really? I don't think it's thatΒ good, I only use MS paint, but thanks! your art is better though!
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jade-winglet-ask In reply to KomaCookie [2019-01-28 18:22:22 +0000 UTC]
Thatβs not true! Your art is really good! ^^
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KomaCookie In reply to jade-winglet-ask [2019-01-28 18:25:40 +0000 UTC]
aw, thanks, really, it's means alotΒ to me!
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jade-winglet-ask In reply to jade-winglet-ask [2019-01-28 18:19:14 +0000 UTC]
Thank you so much for the watch btw <3
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jade-winglet-ask In reply to Queen-Clam [2019-01-17 13:22:57 +0000 UTC]
You're welcome ^^
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jade-winglet-ask In reply to CloudtheDragonet [2019-01-15 14:05:55 +0000 UTC]
Thank you! <3
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Libraryofcharacters [2019-01-10 03:03:36 +0000 UTC]
Thanks so much for the watch! :3
Β Β
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jade-winglet-ask In reply to Libraryofcharacters [2019-01-10 03:17:37 +0000 UTC]
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jade-winglet-ask In reply to Pokenoll [2019-01-04 16:01:32 +0000 UTC]
You're welcome! :>
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Pokenoll In reply to jade-winglet-ask [2019-01-07 21:22:06 +0000 UTC]
And thank you very much for the watch !
I really appreciate it !
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hurricanethedragon [2018-12-28 18:58:28 +0000 UTC]
Thanks so much for watching me back! UwU Your support means a lot to me!
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jade-winglet-ask In reply to hurricanethedragon [2018-12-28 23:30:28 +0000 UTC]
Np :> Iβm relatively new, so thank you so much for your watch! :3
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hurricanethedragon In reply to jade-winglet-ask [2018-12-29 00:57:19 +0000 UTC]
No problem! ^w^
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HappyDeaths In reply to HappyDeaths [2018-12-20 19:06:01 +0000 UTC]
Little gift for an amazing artist π
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jade-winglet-ask In reply to HappyDeaths [2018-12-20 19:49:21 +0000 UTC]
Omg! Thank you so much! She's so cute! :3
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AidenTheHumanY [2018-12-18 04:27:25 +0000 UTC]
Hey will you be accepting Christmas gifts?
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jade-winglet-ask In reply to AidenTheHumanY [2018-12-18 22:46:06 +0000 UTC]
Yes, I will, but you guys donβt have to!
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jade-winglet-ask In reply to XQuillthehybridX [2018-12-02 22:26:15 +0000 UTC]
Thank you so much! :>
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XQuillthehybridX In reply to jade-winglet-ask [2018-12-02 22:28:19 +0000 UTC]
No problem! Count me as ur first watcher!!!!
π: 0 β©: 1
jade-winglet-ask In reply to XQuillthehybridX [2018-12-02 22:42:05 +0000 UTC]
Thank you!
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XQuillthehybridX In reply to jade-winglet-ask [2018-12-02 22:51:48 +0000 UTC]
no prob! Thanks for the watch!
π: 0 β©: 1